解:谨指原式=1÷(2x²+1-x)/让晌桥x=1÷(x²+1)坦猛/x=1×x/(x²+1)=1/(x²+1)
1÷[2x+(1-x²)/x]=1÷(2x²+1-x²)/x=x/(x²+1)
1÷[(x^2+1)/x]=x/(x^2+1)
化简结果x/(x*x+1)
化简=x/(x+1)
(2x^2+1-x^2)/x=1/(1+x^2)/x=x/(1+x^2)