一设原来长X米,则槐山1/4X+﹙3/4X·5/6-4﹚+9=X,可求散明银的X=40二设原来有X升,X-[1/3X+5+1/9﹙X-1/3X-5﹚]+4=12,x=21三冲宴设原来有x,1/5x-1+2/7[x-﹙1/5x-1﹚]+2+13=x,x=25