AC+CD=CE
证明:∵△ABC为罩扮码正三角形,△ADE为正物哪三角形
∴AB=AC=BC
AE=AD
∠BAC=∠DCE=60°
∵∠BAD=∠BAC+∠CAD
∠EAC=∠EAD+∠CAD
∴∠BAD=∠EAC
∵在△ABD和△ACE中
AB=AC
∠BAD=∠缺皮EAC
AE=AD
∴△ABD≌△ACE
∴BD=CE
∵BC=AC
BC+CD=BD
∴AC+CD=BD
∴AC+CD=CE
AC+CD=CE