x=1,y=-1或x=y=3,有题目x≠y,故x=-1,y=1(x+2y)/(x-y)=-0.5
|2x-y|=3,x-2y=3可以分为两种情况情况1:2x-y=3,x-2y=3求猜丛辩得x=1,y=-1;则(x+2y)/(x-y)=-1/2情况2:-2x+y=3,x-2y=3求郑圆得x=-3,y=-3;则(x+2y)/(x-y)无穗缺意义